Find the value of x :X2+3a(2a2)+k=0
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Answer:
We know that while finding the root of a quadratic equation ax
2
+bx+c=0 by quadratic formula x=
2a
−b±
b
2
−4ac
,
if b
2
−4ac>0, then the roots are real and distinct
if b
2
−4ac=0, then the roots are real and equal and
if b
2
−4ac<0, then the roots are imaginary.
Here, the given quadratic equation 2a
2
+3a+p=0 is in the form ax
2
+bx+c=0 where a=2,b=3 and c=p.
It is given that the roots are equal, therefore b
2
−4ac=0 that is:
b
2
−4ac=0
⇒(3)
2
−(4×2×p)=0
⇒9−8p=0
⇒−8p=−9
⇒8p=9
⇒p=
8
9
Hence, p=
8
9
Step-by-step explanation:
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