find the value of x, x² + 5 x + 3 =0
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D = b^2 - 4ac
= (5)^2 - 4 × 1 × 3
= 25 - 12
= 13
x = (-b+-root D )/2a
= (-5+-root 13)/2
HOPE THIS WILL HELP U....
= (5)^2 - 4 × 1 × 3
= 25 - 12
= 13
x = (-b+-root D )/2a
= (-5+-root 13)/2
HOPE THIS WILL HELP U....
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