Question

find the value of (x - y - 2) + 3xy(y - z) when x=-1, y=-1, z=-1​

Answer 1

Answer:

the value of (x - y - 2) + 3xy(y - z) when x=-1, y=-1, z=-1 is

-2

Answer 2

(x-y-2)+3xy(y-z) where x=(-1), y=(-1), z=(-1)

Replacing the values of x, y, z in the given equation we get,

=(-1-1-2)+3(-1)(-1)(-1+1)

=(-4)+3(0)

=(-4)+0

= -4