Math, asked by hasith146, 6 months ago

Find the value of (x+y)^2. If xy = -15 and x-y =6. Please explain the answer and I will mark you as the brainliest​

Answers

Answered by abhaysingh107903642
3

Step-by-step explanation:

Given,

x-y=6

xy=20

now ,

we know that (x-y)^2=x^2+y^2-2xy

now substitute,

6^2=x^2+y^2–2(20)

36=x^2+y^2–40

x^2+y^2=76 -(1)

now ,

we know that, x^3-y^3=(x-y)(x^2+y^2+xy) -(2)

so now substitute values of x-y,xy,equation (1) in equation (2)

x^3-y^3=6(76+20)

=6(96)

=576

therefore, x^3-y^3 = 576

please mark as brainlist

Answered by anandarajanandaraj84
1

Step-by-step explanation:

u see 8am not getting the answer

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