Question

find the value of:- (x+y)^2-(x-y)^2; if x=1/3,y=1/5​

Answer 1

Answer:

2/25

Step-by-step explanation:

we know that

(a + b)^2 = a^2 + 2ab + b^2

(a – b)^2 = a^2 – 2ab + b^2

here in the present question instead of a and b they have mentioned X and Y

(x+y)^2 = x^2 + y^2 +2xy

(x-y)^2 = x^2 + y^2 - 2xy

put them together as in the question

x^2 + y^2 +2xy - x^2 + y^2 - 2xy

+ x^2 and -x^2 gets cancelled

similarly,

+2xy and -2xy gets cancelled

now we are left with-

y^2+y^2= 2y^2

NOW PUT THE VALUE OF Y = 1 / 5 IN THIS EQUATION

2 (1/5)^2

2(1/25)

2/25

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