Question

Find the value of x, y and Z.




.Answer is x =30°,y=70°,z=110°.
.Show me expllenation.​

Answer 1

Answer:

Finding the angles -

➵Angle Z = 100° (vertically opposite angles)

➵Angle x + 40+ 110= 180° (linear pair)

ㅤㅤㅤㅤㅤㅤㅤㅤ=150+x= 180°

ㅤㅤㅤㅤㅤㅤㅤㅤ=x=30°

➵Angle y = x+30(vertically opposite angles)

ㅤㅤㅤㅤ=y= 40+30

ㅤㅤㅤㅤ=y=70°

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Answer-

➵Angle x = 30°

➵Angle y = 70°

➵Angle z = 110°

Answer 2

AnsweR :

• x = 30°
• y = 70°
• z = 110°

SolutioN :

Find x

$\\ \sf \angle \: SOR = 40 \degree (given)\\ \sf \angle \: MOP = 110 \degree(given)$

$\sf \angle \: SOR + \angle \: MOS + \angle \: MOP = 180 \degree[Linear \: pair] \\ \sf = 40 \degree + \angle \: MOS + 110 \degree = 180 \degree \\ \sf = 150 \degree + \angle \: MOS = 180 \degree \\ \sf = \angle \: MOS = 180 \degree - 150 \degree = 30 \degree \\ \sf \angle \: MOS = x = 30 \degree$

__________________________

Find y

$\sf \angle \: MOP + \angle \: POQ = 180 \degree [Linear \: Pair]\\ \sf \angle \: MOP = 110 \degree \\ \sf \angle \: POQ = y \\ \sf = 110 \degree + y = 180 \degree \\ \sf = y = 180 - 110 \\ \sf = y = 70 \degree$

__________________________

Find z

$\sf \angle \: POQ + \angle \: QOR = 180 \degree [Linear \: Pair]\\ \sf \angle \: POQ = 70 \degree \\ \sf \angle \: QOR = z \\ \sf = 70 \degree + = 180 \degree \\ \sf = z= 180 - 70 \\ \sf = z = 110 \degree$