find the value of x,y,and z if Ac and EF are parallel <ADB=?
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Since AC and EF are parallel
therefore, 80° + X° = 180°
X° = 180° - 80°
[ X° = 100°]
Now, In Triangle ADB
30° + 90° + Y° = 180° [sum of all angles in a triangle]
Therefore, Y° = 180° - 120° = 60°
[Y° = 60°]
Since, AC is a straight line
Therefore, 60° + Z° + 80° = 180° [By linear pair axiom]
Z° = 180° - 140°
[Z° = 40°]
X = 100° , Y = 60° , Z = 40°
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