Question

Find the value of x,y and z if x+z=5,y+z=3 and x-y=2

Answer 1

${\underline{\underline{\huge{\mathfrak{\green{Answer:-}}}}}}$

Hey Mate!!

x + z = 5

=> x = 5 - z .......(1)

x - y = 2 ......(2)

By substituting (1) in (2),

5 - z - y = 3

=> -(z + y) = 3 - 5

=> -(z+ y) = -2

=> z + y = 2

But according to question, y + z = 3. Thus the question is wrong...

Answer 2

Answer:

Step-by-step explanation:

Answer:

X = 5, y = 3,z = 0

Step-by-step explanation:

x + z = 5

y + z = 3

x - y = 2

x = z +5

Then in x - y

z + 5 - y =2

z = -3 + y

Then in z + y

y + y - 3 = 3

Y = 3

Then x - y = 2

X = 5

X + z = 5

Z = 0