Math, asked by architagupta223516, 9 days ago

find the value of X y and z in the figure
please don't write wrong answers​

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Answers

Answered by Anonymous
5

Answer:

Answer in attachment pic.

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess

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Answered by TwilightShine
4

Answer :-

  • The value of x = 55°.
  • The value of y = 125°.
  • The value of z = 125°.

To find :-

  • The value of x, y and z in the given figure.

Step-by-step explanation :-

  • Let's find the value of all the angles by using various properties of lines and angles!!

Let's start with x!

-----------------------------------------------------------

  \mid\underline{\boxed{\sf To \:  find \:  the  \: value  \: of \:  x :-}} \mid

  • As we can see in the given figure, x and 55° form vertically opposite angles.

We know that :-

  • Vertically opposite angles are equal.

  • It means that the value of x and 55° is the same.

 \overline{\boxed{ \tt\implies x = 55^{\circ}.}}

  • Hence, the value of x is 55°.

Now let's find the value of y!

-----------------------------------------------------------

  \mid\underline{\boxed{ \sf To  \: find \:  the \:  value  \: of  \: y :-}} \mid

  • As we can see in the given figure, x and y form a linear pair.

We know that :-

  • Linear pairs add up to 180°.

  • This means that the sum of x and y is equal to 180°.

  \tt\implies x + y = 180^{\circ}

Substituting the value of x,

  \tt\implies 55^{\circ} + y = 180^{\circ}

Transposing 55° from LHS to RHS, changing it's sign,

  \tt\implies y = 180^{\circ} - 55^{\circ}

Subtracting the numbers,

  \overline{\boxed{\tt \implies y = 125^{\circ}.}}

  • Hence, the value of y is 125°.

Now finally, let's find the value of z!

-----------------------------------------------------------

  \mid\underline{\boxed{\sf To \:  find  \: the \:  value \:  of  \: z :-}} \mid

  • As we can see in the figure, 55° and z form a linear pair.

We know that :-

  • Linear pairs add up to 180°.

  • This means that the sum of 55° and z is equal to 180°.

 \tt \implies z + 55^{\circ} = 180^{\circ}

Transposing 55° from LHS to RHS, changing it's sign,

 \tt \implies z = 180^{\circ} - 55^{\circ}

Subtracting the numbers,

 \overline{\boxed{\tt \implies z = 125^{\circ}.}}

  • Hence, the value of z = 125°.
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