Math, asked by Anonymous, 5 months ago

find the value of x,y and z.

plz solve it guys plz plz plz plz

plz don't give irrevelent answers ​

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Answers

Answered by MoodyCloud
68
  • Value of x, y and z are 140°, 120° and 60° respectively.

Step-by-step explanation:

To find:-

  • Value of x, y and z.

Solution:-

Let, Two more angles be ∠1 and ∠2 [As given in attachment]

Sum of all interior angles of triangle is equal to 180°. We also say this statement be 'Angle sum property of triangle'.

So,

 \leadsto ∠1 + 110° + 30° = 180°

 \leadsto ∠1 + 140° = 180°

 \leadsto ∠1 = 180° - 140°

 \leadsto ∠1 = 40°

Sum of all angles forms on straight line is equal to 180°. We also say this statement be 'Linear pair'.

So,

 \leadsto ∠1 + x = 180°

 \leadsto 40° + x = 180°

 \leadsto x = 180° - 40°

 \sf \leadsto \pink{\boxed{\sf \bold{x = 140\degree}}\star}

By, Vertically opposite angles

• ∠2 = 30°

Now,

By Angle sum property :

 \leadsto ∠2 + 30° + y = 180°

 \leadsto 30° + 30° + y = 180°

 \leadsto 60° + y = 180°

 \leadsto y = 180° - 60°

 \leadsto \red{\boxed{\sf \bold{y = 120\degree}}\star} \\

 \leadsto z + y = 180° [By Linear pair]

 \leadsto z + 120° = 180°

 \leadsto z = 180° - 120°

 \leadsto \purple{\boxed{\sf \bold{z = 60\degree}}\star}

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Answered by Anonymous
76

Answer:

To Find :-

Find the value of x, y and z

SoluTion :-

Firstly let's divide the figure into two triangle.

As we know that sum of all sides of triangle = 180⁰

Therefore

 \tt \leadsto \: 110 \degree+ 30 \degree + x = 180 \degree

 \tt \leadsto 140 \degree + x = 180 \degree

 \tt \leadsto \: x = 180 \degree - 140 \degree

 {\huge {\mapsto  {\huge {\fbox  {\green {x = 40}}}}}}

Now,

By, Vertically opposite angles

• ∠2 = 30

Now

Lets find y

 \tt \leadsto \angle \: 2 + 30 + y = 180

 \tt \leadsto \: 30 + 30 + y = 180

 \tt \leadsto \: 60 + y = 180

 \tt \leadsto \: y \:  = 180 - 60

  {\huge {\mapsto {\huge {\fbox {\blue {y = 120}}}}}}

Now,

Finding z

 \tt \leadsto  z + y = 180° [By \:  Linear \: pair]

 \leadsto  \tt \: z + 120 = 180

 \tt \leadsto \: z \:  = 180 - 120

{\huge {\mapsto {\huge {\fbox {\red {z = 60}}}}}}


Anonymous: Nice!
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