find the value of x,y for which the lines AD and BC become parallel
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Answer:
Given AD||BC
5y=2x.........(1) [alternate angles]
<BAC=180-5y-30
<BAC=150-5y
(150-5y)+2x+x-y=180°
150-5y+2x+X+y=180°
3x-6y=30
x-2y=10
X=10+2y........(2)
5y=2x......... (1)
X=10+2y.........(2)
Substitute (2) into (1)
5y=2x
5y=2(10+2y)
5y=20+4y
5y-4y=20
y=20°
X=10+2y
X=10+2(20)
X=10+40
X=50°
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