Question

Find the value of (x-y)from the following equation 2x+3y=8 and 3x+2y=12

Answer 1

Answer:

(x-y)=4

Step-by-step explanation:

2x+3y=8--eq1

3x+2y=12--eq2

Multiply eq1 by 2 and eq2 by 3

(2x+3y=8)×2-->4x+6y=16--eq3

(3x+2y=12)×3-->9x+6y=36--eq4

Add eq3 and eq4 we get

5x=20

x=20/5

x=4

Substituting x=4 in eq1

2x+3y=8

-->2(4)+3y=8

-->8+3y=8

-->3y=8-8

-->3y=0

-->y=0/3

-->y=0

Therefore, the value of (x-y)=(4-0)=4