find the value of x-y if 3x+4y=11 and 4x+3y=12
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Answered by
7
Answer:
3x-2y=24 _____ (1)
2x-3y=18 _____ (2)
multiply (1) by 2
6x - 4y = 48
multiply (2) by 3
6x-9y=54
subtracting
6x - 4y = 48
6x - 9y = 54
- + -
___________
5y = -6
y=−
5
−6
3x−2(−
5
6
)=24
=3x+
5
12
=24
=3x=24−
5
12
=
5
120−12
=
5
108
∴x=
5
36
x+y=
5
36−6
=
5
30
=6
x−y=
5
36+6
=
5
42
Answered by
0
Answer:
x-y=1
Step-by-step explanation:
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