find the value of x+y if x2+y2=19 and xy=3
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x^2 + y^2 = (x+y)^2 - 2xy
Substitute the given values
This implies ;
19=(x+y)^2 - 2(3)
19+6 = (x+y)^2
-> (x+y)^2 = 25
(x+y) = 5
Substitute the given values
This implies ;
19=(x+y)^2 - 2(3)
19+6 = (x+y)^2
-> (x+y)^2 = 25
(x+y) = 5
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