find the value of x,y,z
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x = {180-(70+40)} = {180-110} = 70°
Step-by-step explanation:
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Step-by-step explanation:
Given,
AB║ CE
So, case (i)
If we take BD as a transversal of parallel lines AB and CE
∠ECD = ∠ABC [∵corresponding angles]
∴ ∠ABC = z = 40°
Then, case (ii)
∠ACB + ∠ACE + ECD = 180° [∵Linear pair]
=> x + 70° + 40° = 180°
=> x + 110° = 180°
=> x = 180°- 110°
= 70°
According to cases (i) and (ii),
∠BAC + ∠ACB + ∠ABC = 180° [∵Sum of all the interior angles of a triangle]
=> y + 70° + 40° = 180°
=> y + 110° = 180°
=> y = 180°- 110°
= 70°
Hence, x= 70° , y= 70° and z = 40° (Ans)
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