Find the value of x,y,z
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x = 55 ---------------{ reason.. ∠ADB =∠DBC (x) ___alternative interior angles}
y = 105 ------------- { reason.. ∠DAB = ∠DCB (y )___opposite angles}
∠x + ∠y + ∠z = 180 { sum of all interior angles }
55 + 105 +∠z = 180
160 +∠z = 180
∠z = 180 - 160
∠z = 20
→ Hence ∠x = 55, ∠y = 105, ∠z = 20
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