find the value of x y z and t. CD,AB and EF intersect at O
Answers
Answered by
0
Step-by-step explanation:
x:y:z=2:3:5
let the angles be 2u,3u and 5u
∠BOF=∠AOE=x
∘
=2u (Alternete angles)
∠EOD=∠COF=y
∘
=3u (Alternete angles)
∠AOC=∠DOB=z
∘
=5u (Alternete angles)
∠EOD+∠DOB+∠BOF+∠FOC+∠COA+∠AOE+∠=360
∘
3u+5u+2u+3u+5u+2u=360
∘
20u=360
∘
u=
20
360
∘
=18
∘
x=2×18
∘
=36
∘
y=3×18
∘
=54
∘
z=5×18
∘
=90
∘
Answered by
1
Step-by-step explanation:
x:y:z=2:3:5
let the angles be 2u,3u and 5u
∠BOF=∠AOE=x
∘
=2u (Alternete angles)
∠EOD=∠COF=y
∘
=3u (Alternete angles)
∠AOC=∠DOB=z
∘
=5u (Alternete angles)
∠EOD+∠DOB+∠BOF+∠FOC+∠COA+∠AOE+∠=360
∘
3u+5u+2u+3u+5u+2u=360
∘
20u=360
∘
u=
20
360
∘
=18
∘
x=2×18
∘
=36
∘
y=3×18
∘
=54
∘
z=5×18
∘
=90
∘
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