Question

find the value of x, y,z each of the following figures ​

Answer 1

Answer:

i) ∠x = ∠ 55° (Vertically opposite angle)

∠x + ∠y = 180° (Adjacent angles)

55° + ∠y = 180° (Linear pair angles)

Therefore, ∠y=180° - 55° = 125°

∠y = ∠z

Hence, ∠x=55° , ∠y=125° and ∠125°

ii) 25° + x + 40° = 180°

65° + x = 180°

Therefore, x = 180° - 65° = 115°

40° + y = 180° (Linear pairs)

Therefore y = 180° - 40° = 140°

y + z = 180° (Linear pairs)

140° + z = 180°

Therefore z = 180° - 140° = 40°

Hence , x - 115°

y = 140° and z = 40°

Answer 2

i) ∠x = ∠ 55° (Vertically opposite angle)

∠x + ∠y = 180° (Adjacent angles)

55° + ∠y = 180° (Linear pair angles)

Therefore, ∠y=180° - 55° = 125°

∠y = ∠z

Hence, ∠x=55° , ∠y=125° and ∠125°

ii) 25° + x + 40° = 180°

65° + x = 180°

Therefore, x = 180° - 65° = 115°

40° + y = 180° (Linear pairs)

Therefore y = 180° - 40° = 140°

y + z = 180° (Linear pairs)

140° + z = 180°

Therefore z = 180° - 140° = 40°

Hence , x - 115°

y = 140° and z = 40°