Question

find the value of x,y,z from the following. x×y+-6=13×-19 +13×Z​

Answer 1

• Step-by-step explanation:

• x×y+(-6) = x×x+(-6)
• x×y+(-6) = x×x+(-6)so
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+6
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+19
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241 x = -241
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241 x = -241 2
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241 x = -241 2x = -12.5
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241 x = -241 2x = -12.5 hey don't copy
• x×y+(-6) = x×x+(-6)so2x+(-6)=13×-19+13×z2x+(-6)=-260+13 2x =-260+13+62x = -260+192x = -241 x = -241 2x = -12.5 hey don't copyif you copy, then you are <@_@>