find the value of x,y,z in given parallelogram
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let this be abcd
since ab//c2
and ad//b2
and AC is a transversal
therefore angle acd=angle abc (v.o.a)
that is 80+35+angle acb=180(angle on a straight line)
angle acb=180-115=65
therefore angle acb=angle cad
therefore angle cad that is X=65
X+y=180(corr. angles)
65+y=180
y=115
since abcd is a parallelogram
therefore y=z(opposite angles of a parallelogram are equal)
hence z=115
since ab//c2
and ad//b2
and AC is a transversal
therefore angle acd=angle abc (v.o.a)
that is 80+35+angle acb=180(angle on a straight line)
angle acb=180-115=65
therefore angle acb=angle cad
therefore angle cad that is X=65
X+y=180(corr. angles)
65+y=180
y=115
since abcd is a parallelogram
therefore y=z(opposite angles of a parallelogram are equal)
hence z=115
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