Question

Find the value of x+y+z when 2^x3^y5^z=1800.

Answer 1

Answer:

1800=2^3. 3^2. 5^2

x=3,y=2,z=2

x+y+z=3+2+2=7

Answer 2

Given:

2^x3^y5^z=1800.

To find:

The value of x+y+z

Solution:

As we have given the number as 1800

for the solution first, find the prime factorization of the number 1800

• 1800 = 2×2×2×3×3×5×5

here we have

• 1800 = 2³3²5²

So the value of x,  y and z will be 3, 2, 2

So the value of the

• x+y+z
• 3+2+2
• 7

Hence x+y+z = 7