find the value of x,yif the distances of the point(x,y)from(-3,0)as well as from(3,0)are 4
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The distance between (x,y) from (-3,0) is
root (x+3)^2 + y^2 = 4
(x+3)^2 + y^2 = 16
x^2 + y^2 + 6x - 7 = 0 ---- (1)
The distance between (x,y) from (3,0) is
root (x-3)^2 + y^2 = 4
x^2 + y^2 - 6x - 7 = 0 ----- (2)
On solving (1),(2), we get
x = 0
substitute x = 0 in (1), we get
y^2 - 7 = 0
y = root 7.
Hope this helps!
root (x+3)^2 + y^2 = 4
(x+3)^2 + y^2 = 16
x^2 + y^2 + 6x - 7 = 0 ---- (1)
The distance between (x,y) from (3,0) is
root (x-3)^2 + y^2 = 4
x^2 + y^2 - 6x - 7 = 0 ----- (2)
On solving (1),(2), we get
x = 0
substitute x = 0 in (1), we get
y^2 - 7 = 0
y = root 7.
Hope this helps!
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