Math, asked by bajajmahir660, 8 months ago

Find the value of x2 + 1/X^2 , if X-1/X=√3

Answers

Answered by prakashmegha25
1

Answer:

x²+1/x² = 11

Explanation:

Given

x-1/x = 3---(1)

On Squaring equation (1), we get

=> (x-1/x)² = 3²

=> x²+1/x²-2*x*(1/x) = 9

/* By algebraic identity :

(a-b)² = a²+b²-2ab */

=> x²+1/x² - 2 = 9

=> x² + 1/x² = 9 +2

=> x² + 1/x² = 11

Therefore,

x²+1/x² = 11

Answered by trixy123
1

Answer:

x²+1/x²=11

Step-by-step explanation:

x-\frac{1}{x} =3\\\\(x-\frac{1}{x} )^2=3^2\\\\x^2+\frac{1}{x^2} -2(x)(\frac{1}{x} )=9\\\\x^2+\frac{1}{x^2}-2(1)=9\\\\x^2+\frac{1}{x^2}=9+2\\\\x^2+\frac{1}{x^2}=11

hope it helps!

<3

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