find the value of x2+1/x2 when x3+1/x3=5
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x3+1/x3 =5
square both sides
(x3-1/x3)2 = (5)2
x6 +1/x6 - 2×x3×1/x3 =25
x6 + 1/x6 -2 = 25
x6 + 1/x6 = 25+2=27
x2+1/x2 =3
x3+1/x3 =5
square both sides
(x3-1/x3)2 = (5)2
x6 +1/x6 - 2×x3×1/x3 =25
x6 + 1/x6 -2 = 25
x6 + 1/x6 = 25+2=27
x2+1/x2 =3
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