Question

find the value of x2+2xy+y2-4x-6y+1 when x=4 and y=-3​

Answer 1

Answer:

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Step-by-step explanation:

$x^2+2xy+y^2-4x-6y+1 \\\\Putting\:\:x = 4 \:\:and\:\: y=\:-3\\\\(4)^2+2(4)(-3)+(-3)^2-4(4)-6(-3)+1 \\\\16+(-24)+9-(16)-(-18)+1\\\\16-24+9-16+18+1\\\\\:=\:\:\:4$

Answer 2

Answer:

Given

x= 4 and y = -3

$x {}^{2} + 2xy + y {}^{2} - 4x - 6y + 1 \\ = 4 {}^{2} + 2 \times 4 \times ( - 3) + ( - 3) {}^{2} - 4 \times 4 - 6 \times ( - 3) + 1 \\ = 16 + ( - 24) + 9 - 16 + 18 + 1 \\ = 16 - 24 + 9 - 16 + 18 + 1 \\ = 16 + 9 + 18 + 1 - 24 - 16 \\ = 44 - (24 + 16) \\ = 44 - 40 \\ = 4$