Question

Find the value of x2 + y2 + 22
, ifx+y+z = 18 and xy + y2 + x=46.
9 and ab + bc + ac=-15.​

Answer 1

Answer:

Squaring both sides

(x+y+z)2=x2+y2+z2+2(xy+yz+zx)

we can substitute given values

              (x+y+z)2=18+(2×9)

             (x+y+z)2=36

              (x+y+z)=6

hope this will help you

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