find the value of x2+y2
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Answered by
0
Answer:
80
Step-by-step explanation:
we know that (x+y)^2= x^2+y^2+2xy
(x+y)^2-2xy= x^2+y^2
(12)^2-2*32=x^2+y^2
x^2+y^2= 144-64
x^2+y^2= 80
Answered by
0
Answer:
80
Step-by-step explanation:
x+y=12. , xy=32
x2+y2
=(x+y)2-2xy
=(12)2-2×32
144-64=80
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