Question

find the value of (x²+y²) if x+y =12 and XY=14​

Answer 1

Step-by-step explanation:

(x²+y²) = (x+y)(x-y)

Now solve your self!!!

Answer 2

Step-by-step explanation:

Given

$x + y = 12 \\ xy = 14$

$( {x + y)}^{2} = {12}^{2} \\ \\ {x}^{2} + 2xy+ {y}^{2} = 144 \\ \\ {x }^{2} + {y}^{2} + 2xy = 144 \\ \\ {x}^{2} + {y}^{2} + 2(14) = 144 \\ \\ {x}^{2} + {y}^{2} + 28 = 144 \\ \\ {x}^{2} + {y}^{2} = 144 - 28 \\ \\ {x}^{2} + {y}^{2} = 116$