Question

find the value of x2 + y2 + xy.​

Answer 1

Step-by-step explanation:

If x + y = 8 and xy = 12, find the value of (x^2+y^2x

2

+y

2

).

Given,

x + y = 8 and xy = 12

To find, the value of x^2+y^2x

2

+y

2

= ?

∴ x + y = 8

Squaring both sides, we get

(x+y)^2=8^2(x+y)

2

=8

2

⇒ x^{2} +y^{2} +2xy=64x

2

+y

2

+2xy=64

Put xy = 12, we get

⇒ x^{2} +y^{2}x

2

+y

2

+ 2(12) = 64

⇒ x^{2} +y^{2}x

2

+y

2

+ 24 = 64

⇒ x^{2} +y^{2}x

2

+y

2

= 64 - 24 = 40

∴ x^2+y^2x

2

+y

2

= 40

Thus, the value of x^2+y^2x

2

+y

2

= 40

Answer 2

Answer:

Refer to the above attachment .

Mark me as brainliest answer .

Thank you .