Question

find the value of x²-y²+z²+2xz, when x= b-c, y=c-a, z=a-b​

Answer 1

Step-by-step explanation:

(b-c)^2-(c-a)^2+(a-b)^2+2(b-c)(a-b)

=b^2+c^2-2bc-(c^2+a^2-2ac)+(a^2+b^2-2ab)+2(ab-b^2-ac+bc)

=b^2+c^2-2bc-c^2-a^2+2ac+a^2+b^2-2ab+2ab-2b^2-2ac+2bc

=0

Answer 2

Answer:

I guess this is correct answer

Step-by-step explanation:

Hope it helps you