Math, asked by rm1613341, 29 days ago

find the value of ¼x²y²z²×⅔ xyz×(-6yz);where x=2 y=3 and z=1

Answers

Answered by nesschool486
0

Step-by-step explanation:

¼×2².3².1².⅔.2.3.1(-6.3.1)

=¼.36.⅔.6.-18

=9.4.-18

=-648

hence ans is -648

if this is helpful pls mark it as Brainliest

Similar questions