Question

Find the value of x³-3x²y+3xy²-y³ if x=2and y=3​

Answer 1

Answer:

x=(2)

y=(3)

x3-3x2y+3xy2-y3

=(2)3- 3(2)2(3) +3(2)(3)2-(3) 3

=8- 3×4×3 + 3×2×9 -27

=8-36+54-27

=8+54 -(36+27)

=62-63

= -1

I think it's help

it could be answer b

friend you are wrong because it's first not 2 squre

(2) 3

=2×2×2=8

I hope you understand what I try to say you ok yes or no

Answer 2

If x = 2 and y = 3

2 cube -3*(2) square*3 + 3*2* (3)square - (3) cube

4 - 36 + 54 - 27

-32+27

-5 is the answer

I hope you liked my answer.
Thanks for the question