Math, asked by aulakhgurmehak64, 4 months ago

find the value of x³+3x²y+y³ if x =2 and y=3

Answers

Answered by Dhanyatha30

1

x³+3x²y+y³

= x³+3x²y+y³

= 2³+32²3+3³

= 8+62+3+27

= 100

I THINK THIS IS THE ANSWER I HOPE IT HELPS YOU MATE I HOPE YOU HAVE UNDERSTAND MATE

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