find the value of X3 -8y3-36xy-216 if x=2y+6
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(2y+6)3-8y3-36(2y+6)y-216
(2y)3+(6)3+3(2y)(6)(2y+6)-8y3-36(2y2+6y)-216
when u solve this the answer will be
=0
(2y)3+(6)3+3(2y)(6)(2y+6)-8y3-36(2y2+6y)-216
when u solve this the answer will be
=0
rishukhanna:
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find the value of k if (x-2) is a factor ok polynomial 2x3-6x3 +5x+k.
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0
Answer:
so given
x = 2y+6
⇒ x - 2y = 6 ...... (i)
cubing both sides
⇒ x³ - 8y³ - 6xy(x - 2y) = 216
⇒ x³ - 8y³ - 6xy(6) = 216 {since , x - 2y = 6 from i}
⇒x³ - 8y³ - 36xy - 216 = 0
so the value of x³ - 8y³ - 36xy - 216 = 0 ANSWER
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