Math, asked by SSK1111111, 10 months ago

find the value of x³ - 8y³ - 36xy - 216 when X = 2y + 6​

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Answers

Answered by bsssahani
6

Answer:

step by step

  1. value of x=2y+6 (given)
  2. putting value
  3. (2y +6)^3 - 8(2y + 6)^3 - 36(2y - 6)y - 216
  4. (8y + 21) -(64y + 168) - (72y -216)y - 216
  5. 8y + 21 - 64y+168 -216-(72y -216)y
  6. 8y-64y+21+168-216-(72y-216)y
  7. 56y-27-(72y-216)y
  8. 56y-27-72y^2-216y
  9. -160y-72y^2-27  ......... answer
Answered by mgmaluminium
2

Answer:

Step-by-step explanation:

value of x=2y+6 (given)

putting value

(2y +6)^3 - 8(2y + 6)^3 - 36(2y - 6)y - 216

(8y + 21) -(64y + 168) - (72y -216)y - 216

8y + 21 - 64y+168 -216-(72y -216)y

8y-64y+21+168-216-(72y-216)y

56y-27-(72y-216)y

56y-27-72y^2-216y

-160y-72y^2-27

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