Find the value of x³-8y³-36xy-216 when X=2y+6
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Step-by-step explanation:
X^3-8y^3-36xy-216 =(2y+6)^3-8y^3-36(2y+6)y-216....(by putting the value of x)=8y^3+216+36y(2y+6)-8y^3-72y^2-216y-216=8y^3+216+72y^2+216y-8y^3-72y^2-216y-216=0
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