Question

find the value of x3 - x2 + x + 46 if x= 2+3i​

Answer 1

Answer:

x^3-x^2+x+46=7

Step-by-step explanation:

First we find the values in parts,

x=2+3i ....(1)

Squaring both side,

x^2=(2+3i)^2

x^2=2^2+(3i)^2+2\times 2\times 3i

x^2=4-9+12i

x^2=-5+12i  .....(2)

Multiply (1) and (2),

x\times x^2=(2+3i)(-5+12i)

x^3=-10+24i-15i+36i^2

x^3=-10+9i-36

x^3=-46+9i .....(3)

Substitute all (1),(2) and (3) in the equation,

x^3-x^2+x+46

=-46+9i-(-5+12i)+2+3i+46

=-46+9i+5-12i+2+3i+46

=7+0i

=7

The value of the expression is x^3-x^2+x+46=7     if x=2+3i