Question

find the value of x³+y³+12xy-64 if x+y =64​

Answer 1

Step-by-step explanation:

x³ + y³ - 4³ + 3(4xy) (64 = 4³)

(x + y - 4)(x² + y² + 4² - xy - 4y - 4x)

x + y = + 4

( 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)

0 * (x² + y² + 4² - xy - 4y - 4x)

= 0

Answer 2

Answer:

x³ + y³ -12xy + 64 = 0   is the correct answer.

Step-by-step explanation:

I think your question is like this

     x³ +y³ - 12xy + 64     if      x+y = -4​  

If this your question then the solution for it is below.

⇒ [x + y]³ = x³ + y³ + [3xy × (x + y)]

⇒ [-4]³      = x³ + y³ + [3xy × (-4)]

⇒ -64       = x³ + y³ - 12xy

⇒ ∴ x³ + y³ -12xy + 64 = 0          ←ANSWER

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