Question

Find the value of (x³ + y³ + 12xy -64) when x + y = 4.

Answer 1

Answer:

0

Step-by-step explanation:

x^3+y^3+12xy-64

=(x+y)^3-3xy(x+y)+12xy-64

=4^3-3xy.4+12xy-64

=64-12xy+12xy-64

=0

Answer 2

Answer:

using identity ,a+b+c=0 then a^3+b^3+c^3= 3abc