Question

Find the value of x3+y3-12xy+64, when x+y= -4

Answer 1

Answer:

0

Step-by-step explanation:

please find attachment

Answer 2

Answer: zero (0)

Step-by-step explanation:

Since, (x+y) = -4

(x+y)^3 = -64

x^3 + y^3 + 3xy(x+y) = -64

x^3 + y^3 + 3xy(-4) +64 = 0

x^3 + y^3 - 12xy + 64 = 0.

Which is the required answer.

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