find the value of x3+y3-12xy+64 when x+ y=-4
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( x + y )³ = x³+y³+3xy( x+y )
= x³+y³+3xy(-4)
= x³ + y³ - 12xy
According to question
x³ + y³ - 12xy + 64 = ( x + y )³ + 64
= (-4)³ + 64
= 0
= x³+y³+3xy(-4)
= x³ + y³ - 12xy
According to question
x³ + y³ - 12xy + 64 = ( x + y )³ + 64
= (-4)³ + 64
= 0
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