Math, asked by sahilsumly, 1 year ago

Find the value of x³+y³+12xy-64, when x+ y=4

Answers

Answered by Rustomsuresh

3

=(x+y)^3 -3xy(x+y)+12xy-64
=(4)^3-3xy(4)+12xy-64
=64- 12xy +12xy-64 =0

Answered by ramramitvarshney

0

The value of this question is 0

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