Find the value of x³+y³+12xy-64, when x+ y=4
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=(x+y)^3 -3xy(x+y)+12xy-64
=(4)^3-3xy(4)+12xy-64
=64- 12xy +12xy-64 =0
=(4)^3-3xy(4)+12xy-64
=64- 12xy +12xy-64 =0
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