Find the value of x³ + y³ +12xy + 64 when x + y = 4
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question- x³+y³+12xy+64
given that x+y= 4
⇒then use the formula
x³ + y³ = (x + y)(x² - xy + y²)
x³ + y³ - 12xy + 64
x³ + y³ + 4³ - 3(4xy) (64 = 4³)
(x + y + 4)(x² + y² + 4² - xy - 4y - 4x)
x + y = - 4
(- 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)
0 * (x² + y² + 4² - xy - 4y - 4x)
= 0
hope it helps
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