Question

Find the value of x3+y3- 12xy + 64 when x + y = - 4

Answer 1

Hey mate here we are

$first \: the \: equation \\ {x}^{3} + {y}^{3} - 12xy + 64 \\ \\ where \: x + y = - 4 \\ the \: equation \: is \: in \: the \: form \: of \\ ( {a + b)}^{3} = {a}^{3} + 3 {a}^{2} b + 3 a{b}^{2} + {b}^{3} \\ i.e..( {x + y)}^{3} \\ ( { - 4)}^{3 } = -4 \times - 4 \times - 4 = - 64 \\ this \: is \: ur \: ans$

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Answer 2

See this is simple

just do it like this way:

First the  equation x^3+y^3-12xy+64

where x+y= - 4

the equation is in the form of

(a+b)^3=a^3+3a^2b+3ab^2+b^2

i.e. (x+y)^3

(-4)^3=-4*-4*-4=-64

so the answer = -64

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