Find the value of x3+y3- 12xy + 64 when x + y = - 4
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2
See this is simple
just do it like this way:
First the equation x^3+y^3-12xy+64
where x+y= - 4
the equation is in the form of
(a+b)^3=a^3+3a^2b+3ab^2+b^2
i.e. (x+y)^3
(-4)^3=-4*-4*-4=-64
so the answer = -64
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