Find the value of x³+y³-12xy+64 , when x+y= -4 .. Plz explain the ans step by step..And get 15pts
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Answered by
3
Given:
X+y = -4
X+y+4= 0
X³+y³+z³- 3xyz= (x+y+z)(x²+y²+x²-xy-yz-zx)
if x+y+z= 0 , then
X³+y³+z³- 3xyz= (0)(x²+y²+x²-xy-yz-zx)
X³+y³+z³- 3xyz= 0
(x)³+(y)+(4)³- 3×x× y× 4= 0
x³+y³-12xy+64=0
_____________________________
Hope this will help you....
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X+y = -4
X+y+4= 0
X³+y³+z³- 3xyz= (x+y+z)(x²+y²+x²-xy-yz-zx)
if x+y+z= 0 , then
X³+y³+z³- 3xyz= (0)(x²+y²+x²-xy-yz-zx)
X³+y³+z³- 3xyz= 0
(x)³+(y)+(4)³- 3×x× y× 4= 0
x³+y³-12xy+64=0
_____________________________
Hope this will help you....
____________________________
ramya1234:
I did the same-_-
you didn't write 2nd & 4th step.
U could have told me that in the comment section
But u removed the answer-_-
you have posted the attachment & in attachment you can't edit the answer.
dats why i deleted it..
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0
Answer:
Find the value of x³+y³-12xy+64 , when x+y= -4 ..
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