Find the value of x³+y³-12xy+64, when x+y=-4(use identity)
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(x+y)³ = x³+y³+3xy(x+y)
Substituting x+y= -4
(-4)³ = x³+y³+3xy(-4)
-64 = x³+y³-12xy
0 = x³+y³- 12xy +64
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Answer:
x+y)³ = x³+y³+3xy(x+y)
Substituting x+y= -4
(-4)³ = x³+y³+3xy(-4)
-64 = x³+y³-12xy
0 = x³+y³- 12xy +64
Step-by-step explanation:
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