Question

) Find the value of :
x3 - y3 – 23 – 3xyz if x = y + z​

Answer 1

Answer:

Fred of my friends family in 4t

Answer 2

⭐your question :-

                   find the value of  :-$x^3 - y^3 - 23 - 3xyz , if x = y +z$

⭐your answer :-

                     $= (x3 + y3 + z3 - 3xyz)\\ = (x + y + z) (x2 + y2 + z2 - xy - yz - zx)\\= (x + y + z) [(x + y + z)2 - 3(xy + yz + zx)]\\= 9 x (81 - 3 x 23)\\= (9 x 12)\\= 108$

hope it will help you .

⭐thank you .