Question

Find the value of x3-y3-6xy+8 for x=-2,y=-1​

Answer 1

Answer:

Given : x^3-y^3-6xy+8

Here, X= 2 and y=1

putting the values of X and y we get

= 2^3-1^3-6×2×1+8

= 8-1-12+8

= 8-13+8

= -5+8

= 3

Answer =3

Answer 2

x= -2

y= -1

x³-y³-6xy+8

= (-2)³-(-1)³-6(-2)(-1)+8

= -8+1-12+8

= -11

Ans: (-11)

Hope it helps you.