Question

Find the value of x3 – y3

, if x – y = 10/

9

and xy = 5/

3​

Answer 1

Answer:

(x-y)³ =x³-y³ -3xy(x-y)

=(10/9)³ =x³-y³-3*5/3(x-y)

=1000/729=x³-y³-5(10/9)

=1000/729=x³-y³-50/9

=(1000/729)+(50/9)=x³-y³