find the value of x³+y³,if x+y=3 and xy=4
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2
Hey mate Here is your answer.
(x+y)^3=x^3+y^3+3xy(x+y)
3^3=x^3+y^3+3×4(3)
27=x^3+y^3+36
27-36=x^3+y^3
= -9
(x+y)^3=x^3+y^3+3xy(x+y)
3^3=x^3+y^3+3×4(3)
27=x^3+y^3+36
27-36=x^3+y^3
= -9
NICEDAY:
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Answered by
0
=>x^3+y^3= x^3+y^3+3xy(X+y)
=>3^3= x^3+y^3+3.4.3
=>27=x^3+y^3+36
=>27-36=x^3+y^3
=> -9=x^3+y^3
Hope it helps you....
=>3^3= x^3+y^3+3.4.3
=>27=x^3+y^3+36
=>27-36=x^3+y^3
=> -9=x^3+y^3
Hope it helps you....
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